What is the extreme f(x)=2x+1,0<= x<1 ?

The extreme f(x)=2x+1,0<= x<1 is Minimum(0,1)

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extreme f(x)=2x+1,0<= x<1

extreme points

f (x) = 2 x + 1, 0 \leq x < 1

Minimum (0, 1)

Solution steps

Find the critical points:

x = 0

Domain of

2 x + 1, 0 \leq x < 1 : 0 \leq x < 1

Find intervals:

Increasing

: 0 < x < 1

Plug the extreme point

x = 0

into

2 x + 1 \Rightarrow y = 1

Minimum (0, 1)

f (x) = 4 x - 5

6 x + 5 y = - 5

y = e^{x + 1}

arctan (- x - 5) - 7

(x - 2)^{2}

What is the extreme f(x)=2x+1,0<= x<1 ?
The extreme f(x)=2x+1,0<= x<1 is Minimum(0,1)