What is the inverse of f(x)=3x^2+2x-1 ?

The inverse of f(x)=3x^2+2x-1 is (-1+sqrt(3x+4))/3 ,-(sqrt(3x+4)+1)/3

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inverse of f(x)=3x^2+2x-1

inverse

f (x) = 3 x^{2} + 2 x - 1

\frac{- 1 + 3 x + 4}{3}, - \frac{3 x + 4 + 1}{3}

Solution steps

y = 3 x^{2} + 2 x - 1

Replace

x

with

y

x = 3 y^{2} + 2 y - 1

Solve for

y, x = 3 y^{2} + 2 y - 1

\frac{- 1 + 3 x + 4}{3}, - \frac{3 x + 4 + 1}{3}

f (x) = \frac{2 x + 4}{x ^{2} + 2 x - 8}

f (x) = 2 cos (3 x - π)

f (x) = \frac{37}{( 1 - 6 x ) ^{2}}

y = 3 x + 4

f (x) = (x + 1)^{2} + 9

What is the inverse of f(x)=3x^2+2x-1 ?
The inverse of f(x)=3x^2+2x-1 is (-1+sqrt(3x+4))/3 ,-(sqrt(3x+4)+1)/3