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Popular Functions >

f(t)=t^2+19t+60

Solution

f (t) = t^{2} + 19 t + 60

Solution

Domain : - \infty < t < \infty

Range : f (t) \geq - \frac{121}{4}

X Intercepts : (- 4, 0), (- 15, 0), Y Intercepts : (0, 60)

Vertex : Minimum (- \frac{19}{2}, - \frac{121}{4})

Inverse : \frac{- 19 + 4 t + 121}{2}, \frac{- 19 - 4 t + 121}{2}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [- \frac{121}{4}, \infty)

Solution steps

Domain of

t^{2} + 19 t + 60 : - \infty < t < \infty

Range of

t^{2} + 19 t + 60 : f (t) \geq - \frac{121}{4}

Axis interception points of

t^{2} + 19 t + 60 :

X Intercepts

: (- 4, 0), (- 15, 0),

Y Intercepts

: (0, 60)

Vertex of

t^{2} + 19 t + 60 :

Minimum

(- \frac{19}{2}, - \frac{121}{4})

Inverse of

t^{2} + 19 t + 60 : \frac{- 19 + 4 t + 121}{2}, \frac{- 19 - 4 t + 121}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the f(t)=t^2+19t+60 ?
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