What is the extreme f(x)=2x^2+(256)/x+13 ?

The extreme f(x)=2x^2+(256)/x+13 is Minimum(4,109)

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extreme f(x)=2x^2+(256)/x+13

extreme points

f (x) = 2 x^{2} + \frac{256}{x} + 13

Minimum (4, 109)

Solution steps

f^{'} (x) = 4 x - \frac{256}{x ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 4

into

2 x^{2} + \frac{256}{x} + 13 : 109

Minimum (4, 109)

\frac{10}{x}

(- 4, - 2), (- 5, - 6)

s (t) = \frac{4 t}{sin ( t )}

f (x) = 7 x + 5

(x^{2} - 4)^{2}

What is the extreme f(x)=2x^2+(256)/x+13 ?
The extreme f(x)=2x^2+(256)/x+13 is Minimum(4,109)