What is the extreme f(x)=3x^5-4x^3-3x ?

The extreme f(x)=3x^5-4x^3-3x is Maximum(-1,4),Minimum(1,-4)

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extreme f(x)=3x^5-4x^3-3x

extreme points

f (x) = 3 x^{5} - 4 x^{3} - 3 x

Maximum (- 1, 4), Minimum (1, - 4)

Solution steps

f^{'} (x) = 15 x^{4} - 12 x^{2} - 3

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

3 x^{5} - 4 x^{3} - 3 x : 4

Maximum (- 1, 4)

Plug

x = 1

into

3 x^{5} - 4 x^{3} - 3 x : - 4

Minimum (1, - 4)

Maximum (- 1, 4), Minimum (1, - 4)

\frac{1 - 5 t}{6 + t}

f (x) = \frac{2 x - 8}{3 x - 24}

sin (t)

\frac{1}{x ^{2} + 10}

(2) (3)

What is the extreme f(x)=3x^5-4x^3-3x ?
The extreme f(x)=3x^5-4x^3-3x is Maximum(-1,4),Minimum(1,-4)