What is the domain of f(x)=sqrt(x)^4+6(sqrt(x))^2-1 ?

The domain of f(x)=sqrt(x)^4+6(sqrt(x))^2-1 is x>= 0

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domain of f(x)=sqrt(x)^4+6(sqrt(x))^2-1

domain

f (x) = x^{4} + 6 (x)^{2} - 1

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

(0, 3), (- 1, 0)

f (x) = x^{3} + 5

y = 2 x^{2} + 24 x - 6

f (x) = x + 2

f (x) = 5 - \frac{x + 1}{3}

What is the domain of f(x)=sqrt(x)^4+6(sqrt(x))^2-1 ?
The domain of f(x)=sqrt(x)^4+6(sqrt(x))^2-1 is x>= 0