What is the critical 5x^2-48x+20 ?

The critical 5x^2-48x+20 is x= 24/5

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critical 5x^2-48x+20

critical points

5 x^{2} - 48 x + 20

x = \frac{24}{5}

Solution steps

5 x^{2} - 48 x + 20

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{24}{5}

Identify critical points not in

f (x)

domain

Domain of

5 x^{2} - 48 x + 20 : - \infty < x < \infty

All critical points are in domain

x = \frac{24}{5}

y = \frac{3}{4} x - 6

f (y) = y = 2 x + 5

34

11 x - 7 y = 56

5 cos (x)