What is the extreme f(x)=sqrt(81-x^2) ?

The extreme f(x)=sqrt(81-x^2) is Minimum(-9,0),Maximum(0,9),Minimum(9,0)

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extreme f(x)=sqrt(81-x^2)

extreme

Minimum (- 9, 0), Maximum (0, 9), Minimum (9, 0)

Solution steps

f^{'} (x) = - \frac{x}{81 - x ^{2}}

Find intervals:

Increasing

: - 9 < x < 0,

Decreasing

: 0 < x < 9

Plug

x = - 9

into

81 - x^{2} : 0

Minimum (- 9, 0)

Plug

x = 0

into

81 - x^{2} : 9

Maximum (0, 9)

Plug

x = 9

into

81 - x^{2} : 0

Minimum (9, 0)

Minimum (- 9, 0), Maximum (0, 9), Minimum (9, 0)

What is the extreme f(x)=sqrt(81-x^2) ?
The extreme f(x)=sqrt(81-x^2) is Minimum(-9,0),Maximum(0,9),Minimum(9,0)