What is the inverse of f(x)=(x-3)^2+5 ?

The inverse of f(x)=(x-3)^2+5 is sqrt(x-5)+3,-sqrt(x-5)+3

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inverse of f(x)=(x-3)^2+5

inverse

f (x) = (x - 3)^{2} + 5

x - 5 + 3, - x - 5 + 3

Solution steps

y = (x - 3)^{2} + 5

Replace

x

with

y

x = (y - 3)^{2} + 5

Solve for

y, x = (y - 3)^{2} + 5

x - 5 + 3, - x - 5 + 3

\frac{3 x}{2 - x}

f (x) = \frac{4 x}{x + 5}

f (x) = 2 - x^{6} - x^{8}

f (x) = 8 - 2 x

What is the inverse of f(x)=(x-3)^2+5 ?
The inverse of f(x)=(x-3)^2+5 is sqrt(x-5)+3,-sqrt(x-5)+3