What is the perpendicular 5x+7y=8,(5,-2) ?

The perpendicular 5x+7y=8,(5,-2) is y= 7/5 x-9

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perpendicular 5x+7y=8,(5,-2)

perpendicular

5 x + 7 y = 8, (5, - 2)

y = \frac{7}{5} x - 9

Solution steps

Find the line

y = mx + b

perpendicular to

5 x + 7 y = 8

that passes through

(5, - 2)

Find the slope of

5 x + 7 y = 8 : m = - \frac{5}{7}

Compute the slope of the perpendicular line:

m_{p} = \frac{7}{5}

Find the line with slope m=

\frac{7}{5}

and passing through

(5, - 2) : y = \frac{7}{5} x - 9

y = \frac{7}{5} x - 9

f (x) = 2 x + 5 y - 10 = 0

\frac{- 3 x ^{2} + 9 x - 6}{5 x - 5}

f (x) = \frac{8 x - 8}{x + 2}

f (x) = \frac{3 x ^{2} + 5 x - 1}{x + 2}

3 x - 4 = 9

What is the perpendicular 5x+7y=8,(5,-2) ?
The perpendicular 5x+7y=8,(5,-2) is y= 7/5 x-9