What is the domain of f(x)=-sqrt(3+11x-4x^2) ?

The domain of f(x)=-sqrt(3+11x-4x^2) is -1/4 <= x<= 3

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domain of f(x)=-sqrt(3+11x-4x^2)

domain

f (x) = - 3 + 11 x - 4 x^{2}

- \frac{1}{4} \leq x \leq 3

Interval Notation

[- \frac{1}{4}, 3]

Solution steps

Find non-negative values for radicals:

- \frac{1}{4} \leq x \leq 3

The function domain

- \frac{1}{4} \leq x \leq 3

f (x) = \frac{- 2 x - 8}{x ^{2} + 5 x + 4}

(2.125) (98.15)

x^{2} - 5 x + 6

f (x) = \frac{7}{3 + e ^{x}}

What is the domain of f(x)=-sqrt(3+11x-4x^2) ?
The domain of f(x)=-sqrt(3+11x-4x^2) is -1/4 <= x<= 3