What is the inverse of f(x)=3x^2-1 ?

The inverse of f(x)=3x^2-1 is sqrt((x+1)/3),-sqrt((x+1)/3)

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inverse of f(x)=3x^2-1

inverse

f (x) = 3 x^{2} - 1

\frac{x + 1}{3}, - \frac{x + 1}{3}

Solution steps

y = 3 x^{2} - 1

Replace

x

with

y

x = 3 y^{2} - 1

Solve for

y, x = 3 y^{2} - 1

\frac{x + 1}{3}, - \frac{x + 1}{3}

(\frac{1}{2})^{x}

f (x) = (x^{2} - 11 x) \cdot (x + 12)

f (x) = - x^{2} + 2 x - 2

(6 x - 4)^{\frac{1}{2}}

x^{4} - 32 x^{2} + 5

What is the inverse of f(x)=3x^2-1 ?
The inverse of f(x)=3x^2-1 is sqrt((x+1)/3),-sqrt((x+1)/3)