What is the FUNCTION_MANY#domain of y=ln(sqrt(x^2+1)) ?

The FUNCTION_MANY#domain of y=ln(sqrt(x^2+1)) is -infinity <x<infinity

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FUNCTION_MANY#domain of y=ln(sqrt(x^2+1))

domain

y = ln (x^{2} + 1)

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find positive values for logs:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

What is the FUNCTION_MANY#domain of y=ln(sqrt(x^2+1)) ?
The FUNCTION_MANY#domain of y=ln(sqrt(x^2+1)) is -infinity <x<infinity