What is the inverse of f(x)= 1/10 x^2 ?

The inverse of f(x)= 1/10 x^2 is sqrt(10)sqrt(x),-sqrt(10)sqrt(x)

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inverse of f(x)= 1/10 x^2

inverse

f (x) = \frac{1}{10} x^{2}

10 x, - 10 x

Solution steps

y = \frac{1}{10} x^{2}

Replace

x

with

y

x = \frac{1}{10} y^{2}

Solve for

y, x = \frac{1}{10} y^{2}

10 x, - 10 x

2 x - 2

f (x) = 3 x (4 x^{2} + 2)^{\frac{1}{2}}

f (x) = \frac{6}{5} x - 3

\frac{1}{( 3 x ^{2} + 6 )}

f (x) = cos (\frac{1}{5 x})

What is the inverse of f(x)= 1/10 x^2 ?
The inverse of f(x)= 1/10 x^2 is sqrt(10)sqrt(x),-sqrt(10)sqrt(x)