What is the perpendicular y= 3/4 x+3,(3,-3) ?

The perpendicular y= 3/4 x+3,(3,-3) is y=-4/3 x+1

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perpendicular y= 3/4 x+3,(3,-3)

perpendicular

y = \frac{3}{4} x + 3, (3, - 3)

y = - \frac{4}{3} x + 1

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{3}{4} x + 3

that passes through

(3, - 3)

Find the slope of

y = \frac{3}{4} x + 3 : m = \frac{3}{4}

Compute the slope of the perpendicular line:

m_{p} = - \frac{4}{3}

Find the line with slope m=

- \frac{4}{3}

and passing through

(3, - 3) : y = - \frac{4}{3} x + 1

y = - \frac{4}{3} x + 1

(x - 2)^{2} (x - 1)

f (x) = - 1

f (x) = \frac{5 x + 3}{4 x - 1}

\frac{x ^{2} - 4}{x ^{2} - 3 x + 2}

- 2 cot (- 4 x + π)

What is the perpendicular y= 3/4 x+3,(3,-3) ?
The perpendicular y= 3/4 x+3,(3,-3) is y=-4/3 x+1