What is the domain of (x+3)/(x^2-9) ?

The domain of (x+3)/(x^2-9) is x 3

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domain of (x+3)/(x^2-9)

domain

\frac{x + 3}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

f (x) = \frac{7}{x - 2}

f (x) = e^{x} - e^{3 x}

- 9 (x - 3)^{2} + 1

y = x^{9 c o s (x)}

f (x) = 5 x^{2} + 1

What is the domain of (x+3)/(x^2-9) ?
The domain of (x+3)/(x^2-9) is x<-3\lor-3<x<3\lor x>3