What is the range of xsqrt(36-x) ?

The range of xsqrt(36-x) is f(x)<= 48sqrt(3)

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range of xsqrt(36-x)

range

x 36 - x

f (x) \leq 483

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

x 36 - x : x \leq 36

Extreme Points of

x 36 - x :

Maximum

(24, 483),

Minimum

(36, 0)

Find the range for the interval

- \infty < x \leq 36 : - \infty < f (x) \leq 483

Combine the ranges of all domain intervals to obtain the function range

f (x) \leq 483

f (x) = \frac{x}{x ( x + 7 )}

f (x) = x^{2} + 22 x + 117

(- 4.93, 0.87), (- 5.55, 0.9)

(2, 2), (3, 6)

x - \frac{8}{x ^{2}}