What is the f(x)= 1/(1-x^2)-,1<= x<= 1 ?

The f(x)= 1/(1-x^2)-,1 Inverse: sqrt(-(1-x)/x),-sqrt(-(1-x)/x)

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f(x)= 1/(1-x^2)-,1<= x<= 1

f (x) = \frac{1}{1 - x ^{2}} -, 1 \leq x \leq 1

Parity : Even

Inverse : - \frac{1 - x}{x}, - - \frac{1 - x}{x}

Solution steps

Parity of

\frac{1}{1 - x ^{2}} -, 1 \leq x \leq 1 :

Even

Inverse of

\frac{1}{1 - x ^{2}} -, 1 \leq x \leq 1 : - \frac{1 - x}{x}, - - \frac{1 - x}{x}

What is the f(x)= 1/(1-x^2)-,1<= x<= 1 ?
The f(x)= 1/(1-x^2)-,1<= x<= 1 is Parity: Even<br/>Inverse: sqrt(-(1-x)/x),-sqrt(-(1-x)/x)