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Popular >

distance (5,-4),(5,7)

Solution

distance

(5, - 4), (5, 7)

Solution

11

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(5, - 4)

and

(5, 7)

is

= (5 - 5)^{2} + (7 - (- 4))^{2}

Simplify

= 11

Popular Examples

midpoint (2,3),(4,-7)midpoint

(2, 3), (4, - 7)

domain of f(x)=(sqrt(x^2-9x))/(x^2-9x)domain

f (x) = \frac{x ^{2} - 9 x}{x ^{2} - 9 x}

range of 2/(x+3)range

\frac{2}{x + 3}

inflection f(x)=(x+3)^{2/3}inflection points

f (x) = (x + 3)^{\frac{2}{3}}

y = x^{2} - x - 6

Frequently Asked Questions (FAQ)

What is the distance (5,-4),(5,7) ?
The distance (5,-4),(5,7) is 11