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midpoint
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f(x)=-e^xcritical (-x^2+1)/((x^2+1)^2)intercepts of f(x)=-2x^2+4xdomain of f(x)=((x^2-9))/(x-3)range of sqrt(((9+x))/(9-x))
Frequently Asked Questions (FAQ)
What is the midpoint (-1,-9),(5,9) ?
The midpoint (-1,-9),(5,9) is (2,0)