What is the inverse of f(x)= 1/(x^4)-7 ?

The inverse of f(x)= 1/(x^4)-7 is \sqrt[4]{1/(x+7)},-\sqrt[4]{1/(x+7)}

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inverse of f(x)= 1/(x^4)-7

inverse

f (x) = \frac{1}{x ^{4}} - 7

Solution steps

y = \frac{1}{x ^{4}} - 7

Replace

x

with

y

x = \frac{1}{y ^{4}} - 7

Solve for

y, x = \frac{1}{y ^{4}} - 7

f (x) = \frac{8 x}{x + 3}

f (x) = lo g_{2} (x + 4)

f (x) = \frac{( 2 x + 8 )}{( x ^{2} - x )}

f (x) = \frac{x}{2}

f (x) = \frac{- 12 x + x}{4}

What is the inverse of f(x)= 1/(x^4)-7 ?
The inverse of f(x)= 1/(x^4)-7 is \sqrt[4]{1/(x+7)},-\sqrt[4]{1/(x+7)}