What is the inverse of f(x)=(2x^2)/5+1 ?

The inverse of f(x)=(2x^2)/5+1 is sqrt((5x-5)/2),-sqrt((5x-5)/2)

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inverse of f(x)=(2x^2)/5+1

inverse

f (x) = \frac{2 x ^{2}}{5} + 1

\frac{5 x - 5}{2}, - \frac{5 x - 5}{2}

Solution steps

y = \frac{2 x ^{2}}{5} + 1

Replace

x

with

y

x = \frac{2 y ^{2}}{5} + 1

Solve for

y, x = \frac{2 y ^{2}}{5} + 1

\frac{5 x - 5}{2}, - \frac{5 x - 5}{2}

ln (x^{2})

f (x) = \frac{( 2 x ^{2} - 3 x - 20 )}{x - 5}

(1, - 3), (3, - 1)

f (x) = \frac{1}{7} (x^{3} - 1)

\frac{x + 6}{x - 2}

What is the inverse of f(x)=(2x^2)/5+1 ?
The inverse of f(x)=(2x^2)/5+1 is sqrt((5x-5)/2),-sqrt((5x-5)/2)