What is the asymptotes of f(x)=(x^2+1)/(8x-5x^2) ?

The asymptotes of f(x)=(x^2+1)/(8x-5x^2) is Vertical: x=0,x= 8/5 ,Horizontal: y=-1/5

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asymptotes of f(x)=(x^2+1)/(8x-5x^2)

asymptotes

f (x) = \frac{x ^{2} + 1}{8 x - 5 x ^{2}}

Vertical : x = 0, x = \frac{8}{5}, Horizontal : y = - \frac{1}{5}

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 1}{8 x - 5 x ^{2}} : x = 0, x = \frac{8}{5}

Horizontal Asymptotes of

\frac{x ^{2} + 1}{8 x - 5 x ^{2}} : y = - \frac{1}{5}

Slant Asymptotes of

\frac{x ^{2} + 1}{8 x - 5 x ^{2}} :

None

Vertical : x = 0, x = \frac{8}{5}, Horizontal : y = - \frac{1}{5}

x^{2} + 4 x + 2

y = 5 x^{2}

e^{x + 2}

f (x) = \frac{5 x + 1}{- x + 7}

f (x) = \frac{x ^{3} + 4 x ^{2}}{7 x ^{2} - 2}

What is the asymptotes of f(x)=(x^2+1)/(8x-5x^2) ?
The asymptotes of f(x)=(x^2+1)/(8x-5x^2) is Vertical: x=0,x= 8/5 ,Horizontal: y=-1/5