What is the critical f(x)=x^{2/3}(x-4) ?

The critical f(x)=x^{2/3}(x-4) is x=0,x= 8/5

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critical f(x)=x^{2/3}(x-4)

critical points

f (x) = x^{\frac{2}{3}} (x - 4)

x = 0, x = \frac{8}{5}

Solution steps

x^{\frac{2}{3}} (x - 4)

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{8}{5}, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{\frac{2}{3}} (x - 4) : - \infty < x < \infty

All critical points are in domain

x = 0, x = \frac{8}{5}

f (x) = 5 x^{5} - 50 x^{3} + 1600

f (x) = \frac{x}{∣ x + 2 ∣ - 8}

f (x) = \frac{1}{ln ( x )}

f (x) = 2 sin (3 x - π)

f (x) = \frac{4}{x} - 2

What is the critical f(x)=x^{2/3}(x-4) ?
The critical f(x)=x^{2/3}(x-4) is x=0,x= 8/5