What is the inverse of f(x)=6x-x^2,x<= 3 ?

The inverse of f(x)=6x-x^2,x<= 3 is 3-sqrt(-x+9),sqrt(-x+9)+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=6x-x^2,x<= 3

inverse

f (x) = 6 x - x^{2}, x \leq 3

3 - - x + 9, - x + 9 + 3

Solution steps

y = 6 x - x^{2}

Replace

x

with

y

x = 6 y - y^{2}

Solve for

y, x = 6 y - y^{2}

3 - - x + 9, - x + 9 + 3

G

f (x) = (2 x + 7)^{2} - 80

f (x) = \frac{3}{x - 6}

f (x) = 2 x^{3} + 4

What is the inverse of f(x)=6x-x^2,x<= 3 ?
The inverse of f(x)=6x-x^2,x<= 3 is 3-sqrt(-x+9),sqrt(-x+9)+3