What is the domain of f(x)=sqrt(x)+sqrt(6-x) ?

The domain of f(x)=sqrt(x)+sqrt(6-x) is 0<= x<= 6

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domain of f(x)=sqrt(x)+sqrt(6-x)

domain

f (x) = x + 6 - x

0 \leq x \leq 6

Interval Notation

[0, 6]

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 6

The function domain

0 \leq x \leq 6

y = 2 ln (x - 1)

f (x) = 6 x - 2

\frac{2}{3} x

f (x) = \frac{( 5 x - 10 )}{x - 3}

f (x) = x + x

What is the domain of f(x)=sqrt(x)+sqrt(6-x) ?
The domain of f(x)=sqrt(x)+sqrt(6-x) is 0<= x<= 6