What is the domain of sqrt(2x^2-17) ?

The domain of sqrt(2x^2-17) is x = sqrt(17/2)

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domain of sqrt(2x^2-17)

domain

x \leq - \frac{17}{2} or x \geq \frac{17}{2}

Interval Notation

(- \infty, - \frac{17}{2}] \cup [\frac{17}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - \frac{17}{2} or x \geq \frac{17}{2}

The function domain

x \leq - \frac{17}{2} or x \geq \frac{17}{2}

What is the domain of sqrt(2x^2-17) ?
The domain of sqrt(2x^2-17) is x<=-sqrt(17/2)\lor x>= sqrt(17/2)