What is the inverse of f(x)= 1/2 x^3+2 ?

The inverse of f(x)= 1/2 x^3+2 is cube root of 2x-4

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inverse of f(x)= 1/2 x^3+2

inverse

f (x) = \frac{1}{2} x^{3} + 2

Solution steps

y = \frac{1}{2} x^{3} + 2

Replace

x

with

y

x = \frac{1}{2} y^{3} + 2

Solve for

y, x = \frac{1}{2} y^{3} + 2

- 2 sin (- 4 x + \frac{π}{2})

f (x) = 7 (x - 1)^{3}

f (x) = - 1 + (x + 2)^{3}

f (x) = \frac{x - 3}{9 x - x ^{3}}

\frac{( 5 x - 4 )}{7 x + 3}

What is the inverse of f(x)= 1/2 x^3+2 ?
The inverse of f(x)= 1/2 x^3+2 is cube root of 2x-4