What is the range of-3/(|x+2|) ?

The range of-3/(|x+2|) is f(x)<0

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range of-3/(|x+2|)

range

- \frac{3}{∣ x + 2 ∣}

f (x) < 0

Interval Notation

(- \infty, 0)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

- \frac{3}{∣ x + 2 ∣} : x < - 2 or x > - 2

Extreme Points of

- \frac{3}{∣ x + 2 ∣} :

None

Absolute value functions are piecewise functions

Find the function intervals:

x < - 2, x > - 2

Evaluate the function behavior for each interval

Find the range for the interval

- \infty < x < - 2 : - \infty < f (x) < 0

Find the range for the interval

- 2 < x < \infty : - \infty < f (x) < 0

Combine the ranges of all domain intervals to obtain the function range

f (x) < 0 or f (x) < 0

f (x) < 0

\frac{t - 2}{t + 2}

f (x) = - \frac{4}{5} x + 16

f (x) = 9 x^{2} - x + 1

f (x) = 2 - x

f (x) = 5^{x} + 1