What is the asymptotes of f(x)=((x^3+2)/(x^2-9)) ?

The asymptotes of f(x)=((x^3+2)/(x^2-9)) is Vertical: x=-3,x=3,Slant: y=x

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asymptotes of f(x)=((x^3+2)/(x^2-9))

asymptotes

f (x) = (\frac{x ^{3} + 2}{x ^{2} - 9})

Vertical : x = - 3, x = 3, Slant : y = x

Solution steps

Vertical asymptotes of

\frac{x ^{3} + 2}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{x ^{3} + 2}{x ^{2} - 9} :

None

Slant Asymptotes of

\frac{x ^{3} + 2}{x ^{2} - 9} : y = x

Vertical : x = - 3, x = 3, Slant : y = x

f (x) = \frac{1}{x ^{3}}

\frac{1}{1 - \frac{1}{x - 2}}

x^{4} - 4 x^{2}

f (x) = \frac{5 x + 2}{20 x ^{2} - 11 x - 3}

f (x) = x^{2} - 4 x + 7

What is the asymptotes of f(x)=((x^3+2)/(x^2-9)) ?
The asymptotes of f(x)=((x^3+2)/(x^2-9)) is Vertical: x=-3,x=3,Slant: y=x