What is the asymptotes of f(x)=((x+9))/(x^2+4x) ?

The asymptotes of f(x)=((x+9))/(x^2+4x) is Vertical: x=-4,x=0,Horizontal: y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=((x+9))/(x^2+4x)

asymptotes

f (x) = \frac{( x + 9 )}{x ^{2} + 4 x}

Vertical : x = - 4, x = 0, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x + 9}{x ^{2} + 4 x} : x = - 4, x = 0

Horizontal Asymptotes of

\frac{x + 9}{x ^{2} + 4 x} : y = 0

Slant Asymptotes of

\frac{x + 9}{x ^{2} + 4 x} :

None

Vertical : x = - 4, x = 0, Horizontal : y = 0

x^{5} - 4 x^{3}

f (x) = x^{3} - x^{2} - x - 10

f (- 1) = \frac{x - 1}{x + 1}

x^{2}

f (x) = \frac{- 4 x ^{2} + 100}{5 x - 25}

What is the asymptotes of f(x)=((x+9))/(x^2+4x) ?
The asymptotes of f(x)=((x+9))/(x^2+4x) is Vertical: x=-4,x=0,Horizontal: y=0