What is the critical f(x)=(x^2-9)^6 ?

The critical f(x)=(x^2-9)^6 is x=-3,x=0,x=3

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critical f(x)=(x^2-9)^6

critical points

f (x) = (x^{2} - 9)^{6}

x = - 3, x = 0, x = 3

Solution steps

(x^{2} - 9)^{6}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 0, x = 3

Identify critical points not in

f (x)

domain

Domain of

(x^{2} - 9)^{6} : - \infty < x < \infty

All critical points are in domain

x = - 3, x = 0, x = 3

cos (x) - 1

\frac{x}{1 - ln ( x - 5 )}

7 x + 10 y = 3

y = \frac{1}{x ^{4}}

\frac{x}{x - 9}

What is the critical f(x)=(x^2-9)^6 ?
The critical f(x)=(x^2-9)^6 is x=-3,x=0,x=3