What is the domain of f(x)=2sqrt(x)+1 ?

The domain of f(x)=2sqrt(x)+1 is x>= 0

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domain of f(x)=2sqrt(x)+1

domain

f (x) = 2 x + 1

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

1 - x

lo g_{3} (8 x) + 9

\frac{x - 3}{x - 1}

f (x) = (\frac{1}{2})^{x - 5} + 2

f (x) = \frac{5 e ^{x} - 8}{e ^{x} + 10}