What is the critical f(x)=-x^4+3x^2-3 ?

The critical f(x)=-x^4+3x^2-3 is x=-sqrt(3/2),x=0,x=sqrt(3/2)

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critical f(x)=-x^4+3x^2-3

critical points

f (x) = - x^{4} + 3 x^{2} - 3

x = - \frac{3}{2}, x = 0, x = \frac{3}{2}

Solution steps

- x^{4} + 3 x^{2} - 3

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{3}{2}, x = 0, x = \frac{3}{2}

Identify critical points not in

f (x)

domain

Domain of

- x^{4} + 3 x^{2} - 3 : - \infty < x < \infty

All critical points are in domain

x = - \frac{3}{2}, x = 0, x = \frac{3}{2}

f (x) = \frac{x ^{2} + 10 x + 9}{2 x + 2}

y = x^{2} - 2 x - 24

f (x) = 1 - x

y = - x + 13, (- 8, 7)

8 x + 2

What is the critical f(x)=-x^4+3x^2-3 ?
The critical f(x)=-x^4+3x^2-3 is x=-sqrt(3/2),x=0,x=sqrt(3/2)