What is the domain of (sqrt(4-x))(sqrt(x^2-1)) ?

The domain of (sqrt(4-x))(sqrt(x^2-1)) is x<=-1\lor 1<= x<= 4

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domain of (sqrt(4-x))(sqrt(x^2-1))

domain

(4 - x) (x^{2} - 1)

x \leq - 1 or 1 \leq x \leq 4

Interval Notation

(- \infty, - 1] \cup [1, 4]

Solution steps

Find non-negative values for radicals:

x \leq - 1 or 1 \leq x \leq 4

The function domain

x \leq - 1 or 1 \leq x \leq 4

f (x) = \frac{( x + 2 )}{x}

f (x) = \frac{7 x ^{2} - 7}{4 x}

4

x^{\frac{1}{4}}

f (x) = sin (\frac{27 π}{4})

What is the domain of (sqrt(4-x))(sqrt(x^2-1)) ?
The domain of (sqrt(4-x))(sqrt(x^2-1)) is x<=-1\lor 1<= x<= 4