What is the critical (x^3)/((x-1)^2) ?

The critical (x^3)/((x-1)^2) is x=0,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical (x^3)/((x-1)^2)

critical points

\frac{x ^{3}}{( x - 1 ) ^{2}}

x = 0, x = 3

Solution steps

\frac{x ^{3}}{( x - 1 ) ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 3, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{3}}{( x - 1 ) ^{2}} : x < 1 or x > 1

\frac{x ^{3}}{( x - 1 ) ^{2}}

is not defined at

x = 1

, therefore:

x = 0, x = 3

r (x) = \frac{5 x ^{3}}{x ^{3} + 2 x ^{2} + 5 x}

x^{3} + x^{2} - 3 x - 1

f (x) = - x^{2} - 8

- 5 sin (6 x + \frac{π}{2})

- sin (\frac{x}{2}) + 2