What is the inverse of f(x)=sqrt(x^2+4x) ?

The inverse of f(x)=sqrt(x^2+4x) is -2+sqrt(x^2+4),-sqrt(x^2+4)-2

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inverse of f(x)=sqrt(x^2+4x)

inverse

f (x) = x^{2} + 4 x

- 2 + x^{2} + 4, - x^{2} + 4 - 2

Solution steps

y = x^{2} + 4 x

Replace

x

with

y

x = y^{2} + 4 y

Solve for

y, x = y^{2} + 4 y

- 2 + x^{2} + 4, - x^{2} + 4 - 2

(x + 1)^{3}

x^{2} - 4

x = 5

f (x) = t^{4} - 20 t^{3} + 88 t^{2}

What is the inverse of f(x)=sqrt(x^2+4x) ?
The inverse of f(x)=sqrt(x^2+4x) is -2+sqrt(x^2+4),-sqrt(x^2+4)-2