What is the critical f(x)=42x-7x^2 ?

The critical f(x)=42x-7x^2 is x=3

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critical f(x)=42x-7x^2

critical points

f (x) = 42 x - 7 x^{2}

x = 3

Solution steps

42 x - 7 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 3

Identify critical points not in

f (x)

domain

Domain of

42 x - 7 x^{2} : - \infty < x < \infty

All critical points are in domain

x = 3

f (x) = \frac{9}{x - 4}

f (x) = \frac{x ^{2}}{x ^{2} + 3}

f (x) = x - 1 + 2 y = 2

f (x) = \frac{5 x ^{3} - 8}{4 x ^{2} + 5 x}

f (x) = \frac{1}{3} e^{2 x} - 1