What is the inverse of (1-e^{-x})/(1+e^{-x)} ?

The inverse of (1-e^{-x})/(1+e^{-x)} is -ln((1-x)/(x+1))

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inverse of (1-e^{-x})/(1+e^{-x)}

inverse

\frac{1 - e ^{- x}}{1 + e ^{- x}}

- ln (\frac{1 - x}{x + 1})

Solution steps

y = \frac{1 - e ^{- x}}{1 + e ^{- x}}

Replace

x

with

y

x = \frac{1 - e ^{- y}}{1 + e ^{- y}}

Solve for

y, x = \frac{1 - e ^{- y}}{1 + e ^{- y}}

- ln (\frac{1 - x}{x + 1})

(0.54, 1 0^{16}), (1307.9, 1 0^{17})

\frac{1}{x} + 2

f (x) = \frac{x ^{3}}{27}

0

f (x) = \frac{x ^{2} - 4 x + 4}{x - 2}

What is the inverse of (1-e^{-x})/(1+e^{-x)} ?
The inverse of (1-e^{-x})/(1+e^{-x)} is -ln((1-x)/(x+1))