What is the asymptotes of f(x)=(x^2+4x-5)/(x^2-9) ?

The asymptotes of f(x)=(x^2+4x-5)/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=1

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asymptotes of f(x)=(x^2+4x-5)/(x^2-9)

asymptotes

f (x) = \frac{x ^{2} + 4 x - 5}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 4 x - 5}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{x ^{2} + 4 x - 5}{x ^{2} - 9} : y = 1

Slant Asymptotes of

\frac{x ^{2} + 4 x - 5}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 1

x^{2} - 1 x = 1

- 2 sin (x)

f (x) = x^{2} - 1

f (x) = 5 x^{2} + 2 x - 1

f (x) = - 5 + x + x^{2}

What is the asymptotes of f(x)=(x^2+4x-5)/(x^2-9) ?
The asymptotes of f(x)=(x^2+4x-5)/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=1