What is the inverse of 8/(sqrt(x^2-81)) ?

The inverse of 8/(sqrt(x^2-81)) is (sqrt(64+81x^2))/x ,-(sqrt(64+81x^2))/x

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inverse of 8/(sqrt(x^2-81))

inverse

\frac{8}{x ^{2} - 81}

\frac{64 + 81 x ^{2}}{x}, - \frac{64 + 81 x ^{2}}{x}

Solution steps

y = \frac{8}{x ^{2} - 81}

Replace

x

with

y

x = \frac{8}{y ^{2} - 81}

Solve for

y, x = \frac{8}{y ^{2} - 81}

\frac{64 + 81 x ^{2}}{x}, - \frac{64 + 81 x ^{2}}{x}

f (x) = x^{\frac{1}{7}} (x + 8)

f (x) = \frac{5}{x - 7}

x = - 1, (0, 0)

f (x) = x - 4

What is the inverse of 8/(sqrt(x^2-81)) ?
The inverse of 8/(sqrt(x^2-81)) is (sqrt(64+81x^2))/x ,-(sqrt(64+81x^2))/x