What is the perpendicular 2x+5y=10 ?

The perpendicular 2x+5y=10 is y= 5/2 x+b

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perpendicular 2x+5y=10

perpendicular

2 x + 5 y = 10

y = \frac{5}{2} x + b

Solution steps

Find the slope of

2 x + 5 y = 10 : m = - \frac{2}{5}

Compute the slope of the perpendicular line:

m_{p} = \frac{5}{2}

Line with slope m=

\frac{5}{2} : y = \frac{5}{2} x + b

y = \frac{5}{2} x + b

- x^{2} + 6 x - 5

x + y = - 1

f (x) = 9 (x - 2)

f (x) = 1 + \frac{1}{x - 3}

\frac{x + 1}{x - 1}