What is the shift f(t)=-cos(t-pi/6)+1 ?

The shift f(t)=-cos(t-pi/6)+1 is Phase: pi/6 , Vertical:1

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shift f(t)=-cos(t-pi/6)+1

shift

f (t) = - cos (t - \frac{π}{6}) + 1

Phase : \frac{π}{6}, Vertical : 1

Solution steps

f (x) = - cos (t - \frac{π}{6}) + 1

g (B x - C) = cos (t - \frac{π}{6}), B = 1, C = \frac{π}{6}, D = 1

Therefore, the phase shift

\frac{C}{B}

\frac{\frac{π}{6}}{1}

\frac{π}{6}

The vertical shift

D

1

1

\frac{x ^{3} - x ^{2} - x + 1}{x ^{2} - 4}

3 x + 2 y = 8

f (x) = 5 x - 35

f (x) = x^{2} - x

y = x - 3

What is the shift f(t)=-cos(t-pi/6)+1 ?
The shift f(t)=-cos(t-pi/6)+1 is Phase: pi/6 , Vertical:1