What is the inverse of f(x)=x^2+4,x>= 0 ?

The inverse of f(x)=x^2+4,x>= 0 is sqrt(x-4),-sqrt(x-4)

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inverse of f(x)=x^2+4,x>= 0

inverse

f (x) = x^{2} + 4, x \geq 0

x - 4, - x - 4

Solution steps

y = x^{2} + 4

Replace

x

with

y

x = y^{2} + 4

Solve for

y, x = y^{2} + 4

x - 4, - x - 4

f (x) = \frac{( 6 x ^{2} - 5 )}{( 2 x ^{2} + 6 )}

\frac{( 1 )}{( - 10 ( \frac{( 1 )}{( - 5 x - 6 )} ) + 3 )}

3 x^{2}

(- 4) (6)

\frac{1 - 4 t}{3 + t}

What is the inverse of f(x)=x^2+4,x>= 0 ?
The inverse of f(x)=x^2+4,x>= 0 is sqrt(x-4),-sqrt(x-4)