What is the domain of f(x)=sqrt(x^2+x) ?

The domain of f(x)=sqrt(x^2+x) is x = 0

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domain of f(x)=sqrt(x^2+x)

domain

f (x) = x^{2} + x

x \leq - 1 or x \geq 0

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 0

The function domain

x \leq - 1 or x \geq 0

f (x) = \frac{x - 1}{x ^{2} - 4 x + 3}

f (x) = (x + 3)^{3} - 1

m = - \frac{7}{16}

(x^{2} - 9)^{6}

x^{4}

What is the domain of f(x)=sqrt(x^2+x) ?
The domain of f(x)=sqrt(x^2+x) is x<=-1\lor x>= 0