What is the extreme f(x)=4x^3-48x-3 ?

The extreme f(x)=4x^3-48x-3 is Maximum(-2,61),Minimum(2,-67)

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extreme f(x)=4x^3-48x-3

extreme points

f (x) = 4 x^{3} - 48 x - 3

Maximum (- 2, 61), Minimum (2, - 67)

Solution steps

f^{'} (x) = 12 x^{2} - 48

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

4 x^{3} - 48 x - 3 : 61

Maximum (- 2, 61)

Plug

x = 2

into

4 x^{3} - 48 x - 3 : - 67

Minimum (2, - 67)

Maximum (- 2, 61), Minimum (2, - 67)

6 x^{2} + 12 x

y = 1.1 x

y = \frac{x ^{2} + 3 x + 7}{2 x - 1}

cos^{x} (x)

x + 15

What is the extreme f(x)=4x^3-48x-3 ?
The extreme f(x)=4x^3-48x-3 is Maximum(-2,61),Minimum(2,-67)