What is the critical f(x)=x^3+2x^2+x-7 ?

The critical f(x)=x^3+2x^2+x-7 is x=-1,x=-1/3

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critical f(x)=x^3+2x^2+x-7

critical points

f (x) = x^{3} + 2 x^{2} + x - 7

x = - 1, x = - \frac{1}{3}

Solution steps

x^{3} + 2 x^{2} + x - 7

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = - \frac{1}{3}

Identify critical points not in

f (x)

domain

Domain of

x^{3} + 2 x^{2} + x - 7 : - \infty < x < \infty

All critical points are in domain

x = - 1, x = - \frac{1}{3}

e^{x^{2}}

2

(2 x - 1)^{7} (x + 5)^{6}

f (x) = \frac{4 x + 3}{- 5 x + 2}

What is the critical f(x)=x^3+2x^2+x-7 ?
The critical f(x)=x^3+2x^2+x-7 is x=-1,x=-1/3