What is the critical f(x)= 1/2 x^2+5x+4 ?

The critical f(x)= 1/2 x^2+5x+4 is x=-5

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critical f(x)= 1/2 x^2+5x+4

critical points

f (x) = \frac{1}{2} x^{2} + 5 x + 4

x = - 5

Solution steps

\frac{1}{2} x^{2} + 5 x + 4

Find where

f^{'} (x)

is equal to zero or undefined

x = - 5

Identify critical points not in

f (x)

domain

Domain of

\frac{1}{2} x^{2} + 5 x + 4 : - \infty < x < \infty

All critical points are in domain

x = - 5

tan (x + \frac{π}{2})

11 sin (8 t)

f (x) = \frac{3}{x - 4}

y = - \frac{5}{6} x + \frac{1}{6}, (5, - 4)

What is the critical f(x)= 1/2 x^2+5x+4 ?
The critical f(x)= 1/2 x^2+5x+4 is x=-5