What is the critical f(x)=4x^3-16x ?

The critical f(x)=4x^3-16x is x=-2/(sqrt(3)),x= 2/(sqrt(3))

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critical f(x)=4x^3-16x

critical points

f (x) = 4 x^{3} - 16 x

x = - \frac{2}{3}, x = \frac{2}{3}

Solution steps

4 x^{3} - 16 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{2}{3}, x = \frac{2}{3}

Identify critical points not in

f (x)

domain

Domain of

4 x^{3} - 16 x : - \infty < x < \infty

All critical points are in domain

x = - \frac{2}{3}, x = \frac{2}{3}

4 x^{3} - 5 x^{2} + 2 x - 1

x - 3 y = 6

x + y = - 1

f (x) = \frac{x - 5}{x + 3}

f (x) = 6 x - 3 y = - 2

What is the critical f(x)=4x^3-16x ?
The critical f(x)=4x^3-16x is x=-2/(sqrt(3)),x= 2/(sqrt(3))