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midpoint
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inverse of f(x)=1-sqrt(x)domain of (12)/xparity 7x+5inverse of (3x)/(x+7)asymptotes of f(x)=(x^2-4x)/(x^4-256)
Frequently Asked Questions (FAQ)
What is the midpoint (7,4),(9,-1) ?
The midpoint (7,4),(9,-1) is (8, 3/2)